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Here’s where the math magic happens. We're going to use the tangent function (tan) to relate the angles, the distances, and the height. For the angle of elevation, we have: tan(30°) = (h - 10) / *x*. For the angle of depression, we have: tan(60°) = (h + 10) / *x*. Now, we can solve for *x* in both equations: *x* = (h - 10) / tan(30°) and *x* = (h + 10) / tan(60°). Since both equations equal *x*, we can set them equal to each other: (h - 10) / tan(30°) = (h + 10) / tan(60°). We know that tan(30°) = 1/√3 and tan(60°) = √3. Substitute these values into the equation: (h - 10) / (1/√3) = (h + 10) / √3. Simplify: (h - 10) * √3 = (h + 10) / √3. Multiply both sides by √3: 3(h - 10) = h + 10. Solve for h: 3h - 30 = h + 10. Subtract h from both sides: 2h - 30 = 10. Add 30 to both sides: 2h = 40. Divide by 2: h = 20. Thus, the cloud's height above the water surface is 20 meters. Also, we could calculate the value of *x* too. This is how we come to our solution using trigonometric ratios.
